It is well known that a strictly convex minimand admits at most one minimizer. We prove a partial converse: Let XX be a locally convex Hausdorff space and f ⁣:X→(−∞,∞]f\colon X\to (-\infty, \infty] a function with compact sublevel sets and exhibiting some mildly superlinear growth. Then each tilted minimization problem
min⁡x∈Xf(x)−⟨x′,x⟩X\displaystyle \min_{x \in X} f(x) - \langle x', x \rangle_X
admits at most one minimizer as x′x' ranges over dom (∂f∗)\text{\rm dom}\, \left( \partial f^* \right) if and only if the biconjugate f∗∗f^{**} is essentially strictly convex and agrees with ff at all points where f∗∗f^{**} is subdifferentiable. We prove this via a representation formula for f∗∗f^{**} that might be of independent interest.

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